Question

1.solve for x
(a)abslutevalue of(4x-1)+absol(x-2)=4
(b)Absol(11x-22)=-11

Answer 1

|4x-1| + |x-2|=4

Answer 2

\[\left| 4x-1 \right|+\left| x-2 \right|=4\]

Answer 3

Yeah it is like this thanks guys!!!

Answer 4

|x-2|=4-|4x-1|

Answer 5

i tried but i nedd ur answer

Answer 6

What answer did you get ?

Answer 7

@neba.zi ?

Answer 8

solution set are x=-1/5,7/5,1

Answer 9

Yeah now check.

Answer 10

i tired using sign chart first u find th zero of 4x-1& x-2 then arrange increasing order
x<1/4 1/4 (1/4,2) 2 x>2
4x-1 --------------0++++++++++++++++
x-2 -------------------------------0++++++
let us take cases
Case1If X<1/4
-(4x-1)-(x-2)=4 solve this u will get
x=-1/5
Case2 If 1/4<x<2
4x-1-(x-2)=4 then solve this
x=1
Case3 x>2
4x-1+x-2=4 again solve this
x=7/5
Finally u got three solutions that satisfy the These are -1/5,1,7/5
I think it is clear OK try b Hurry up!!!!!

Answer 11

You got these three answer but you have to check by putting

x=-1/5,1,7/5

And you will see that 7/5 is not a solution :)


so your final answer would be

x=-1/5,1

Answer 12

I think the 2nd question is easy Hurry up!!! Take a great care for this question!!!!