Question

find the zeros of h(x)=x^4+4x^3+x^2-8x-6

Answer 1

i can easily find 1 root with hit and trial..how about you ?

Answer 2

I'm completely lost.

Answer 3

infact, try rational root theroem, 2 of the roots i could find easily..

Answer 4

Can you explain the rational root theroem?

Answer 5

for any polynomial of the form
ax^n + ........ +b = 0

if the eqn has any rational roots, it'll be of the form
+- (factors of b)/(factors of a)

this is rational root theorem, which can understood easily using vieta's formulae ..

Answer 6

in your question ,
b=6
a=1

so roots will be of the form
+- (factors of 6)/(factors of 1)
= +- ( 3,2,1)/(1)

=> 1,2,3, -1,-2,-3

2 out them i found out were roots..

Answer 7

x+3 is a factor

Answer 8

x^4+4x^3+x^2-8x-6 x+3 is a factor nw use Long Division

Answer 9

infact,
since you can make out 2 roots from the rational root theorem, for the other 2,
use sum of roots, or product of roots or any other roots thing so as to find the other 2.