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\sqrt{2x+3}=2+\sqrt{x-2}
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\[2+\sqrt{x-2}\] Is it equal to 0 ?
Yeah
\[2+\sqrt{x-2}=0\] 1) Subtract 2 on both sides 2) Squaring both sides
Start working @getexcool
i got 6??
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@getexcool Respond....
Well the question was suppose to be Sqrt:2x+3=2+sqrt:x-2
For the first part I got 2x+3 cuz I am suppose to square both sides with 2
The question is \[\sqrt{2x+3}=2+\sqrt{x-2}\] ?
That's correct
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Apply squaring both sides on this \[( \sqrt{2x+3})^2=(2+\ \sqrt{x-2})^2\]
Use (a+b)^2=a^2+2ab+b^2
I got x=3 is that the right answer
@hba
Put the value in your question and check if LHS=RHS if yes then you are correct :)
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