In a race, Brian Collins has to cross 10 hurdles. The probability that he clears a hurdle is . Find the probability. P(at least three hurdles are cleared)
An important thing to recognize here is that he can only clear some number of hurdles each run. This means that clearing 2 hurdles and clearing 3 hurdles are mutually exclusive events. Thus: \[ \Pr(X \geq 3) = \Pr(X = 3) + \Pr(X = 4) +\Pr(X = 5) + ... \]
However, this is a cumbersome operation since we have to calculate 7 probabilities. If we consider the probability of that he clears no more than three hurdles: \[ \Pr(X<3) = \Pr(X=0) + \Pr(X=1) + \Pr(X=2) \]As you can see, this is much easier to calculate. The reason why we can do this is because we know:\[ \Pr(X \geq 3) + \Pr(X<3) = 1 \] That is, the probability of an event happening or not happening is 1. Either has to happen.
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