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Mathematics 16 Online
OpenStudy (anonymous):

Use a truth table to determine whether [(q<->p)^p]->q is a tautology, a self-contradiction, or neither.

OpenStudy (anonymous):

Make a truth table for \[ q \iff p \]Then make one for \[ (q\iff p) \wedge p \]

OpenStudy (anonymous):

Okay... :) Workin on it as we speak!

OpenStudy (anonymous):

then add the final column \[ [(q\iff p)\wedge p ]\implies q \]

OpenStudy (anonymous):

Thank you so much!! So, would it be a self-contradiction??

OpenStudy (anonymous):

I know tautology is always true and I think self-contradiction is always false.

OpenStudy (anonymous):

Alright.... so what would that mean for my answer? Im sorry, Im cramming for a semester exam and I have never seen this before :(

OpenStudy (experimentx):

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