A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account? Which of the following equations could be used to solve the problem?

Question

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?    Which of the following equations could be used to solve the problem?

anonymous · Answer

Are you going to list the equations that follow?

anonymous · Answer

It depends on the rate at which the Annual Percentage Rate (APR).  If those rates are APR then the answer would be $1,333.34	and $2,133.34.

anonymous · Answer

let the amount be x 
then by the prob  (2x)/100  + 4(x+800) )/100=112
 or (2x+4x+3200)/100=112
or 6x+3200=11200
or 6x = 112 00 -3200
or x= 8000/6=1,333.34

$1,333.34 in 2% and $2,133.34 in 4%

anonymous · Answer

0.02x + (x + 800)*0.04 = 112 seems clearer.