Question

Please find attachment below?

Answer 1

First Attachment is no 5 and a=second attachment is no 4

Answer 2

For question no 5 i need help with B,C,D,E

Answer 3

While for question no 4 I need help with question no A,,C,D

Answer 4

For num 5b, go ahead and use the position formula that we used before to calculate how far each went after 6 sec and the answer is the difference.

For num 5c, the instantaneous acceleration will be the rate of change in the velocity, which will be the slope of the line at that point.

For num5d, the average velocity will be the initial velocity+final velocity then divide the sum by 2.

For num 5e, you are basically just sketching the derivative of the velocity vs time graph you are given so that should be easy enough.

Answer 5

For num 4a, the velocity is positive when the distance is increasing.

For num 4c, use the average velocity formula again.

For num4d, you should just be able to take the value straight form the graph.

Hope that helps, good luck

Answer 6

What is the acceleration of 5b.

Answer 7

do you need it?

Answer 8

s=ut+1/2 at^2 is the position formular we used in the previous question. so i thinks will need a

Answer 9

since the acceleration is constant, you should be able to calculate it from the graph, remember that it is the change in velocity/time

Answer 10

Note: the acceleration is constant until t=6, than it changes

Answer 11

is the accceleration constant both for A and B or just B. look at A very. so i will find A by findind slope at t=6

Answer 12

is a going to be the same for both

Answer 13

no, the other car's acceleration is constant here and there, but it changes often enough to be considered time dependent.

Answer 14

for NO 4a is the velocity positive when velocity constant i.e 3-5 sec

Answer 15

so wats going to be the acceleration for A.

Answer 16

well it would be constant, but i wouldn't consider it positive or negative, it is totally static

Answer 17

on num 5?

Answer 18

yeah acceleration of a number 5

Answer 19

No 4d is distance negative, or hould i just ignore the distance

Answer 20

ignore the sign i mean

Answer 21

also for 4c distance/time is the distance going to be -4

Answer 22

yeah, the distance between them would be the absolute value of the difference, negative distance makes no sense ;p

and for #5, the acceleration changes over time so it is not one value unless your talking about at a point

Answer 23

5e i did not get what you mean

Answer 24

oh sorry you haven't taken calc i take it. Ok well let me explain it another way. Anytime the velocity is increasing, acceleration will be positive (above the x-axis), anytime the velocity is decreasing, the acceleration will be negative (below x-axis).

At the point where the velocity switches from increasing to decreasing or vice versa, the acceleration will be zero

Answer 25

also when the velocity is constant the acceleration will be zero

Answer 26

when you take calc physics makes a lot more sense ;p hang in there

Answer 27

i am good and clear with every single thing we just did now jus the Acceleration of no 5 vechile A

Answer 28

ok, so they are talking about the first 5 secs where the acceleration is constant. So take the slope for that line (change in velocity with respect to time dv/dt) or use
change in y/change in x =25/5 = 5 of whatever units it was in

Answer 29

is that all? but its at 6 nt 5 that what i did not get

Answer 30

Thanks Lot Mr Doe really really really Appreciate. i do not know how to thank you.

Answer 31

np, your interest in physics is thanks enough

Answer 32

Hello i tried sketching the acceleration time graph. is it a straight? thanks

Answer 33

yeah the acceleration is constant so it should be a straight line for the first 5 secs

Answer 34

something like this i guess. i however ignored the time whicch the slope is constant between 5 and 8.

Answer 35

its going to look more like this since the acceleration stops and becomes zero before increasing a few seconds later

Answer 36

i do not know how to keep thanking you mr Doe. thanks alot.