Question

A swimmer travels from the south end to the north end of a 30.0 m pool in 15.0 s and makes the return trip to the starting position in 19.0 s. What is the average velocity for the roundtrip?
a.
2.50 m/s to the south
c.
2.50 m/s to the north
b.
2.27 m/s to the north
d.
0.0 m/s

Answer 1

it's not A

Answer 2

average velocity = total distance travelled
------------------
total time taken

Answer 3

ok uh velocity = distance/time

x = 30/15
x = 30/19

Answer 4

total distance = 2*30 meters
total time = 15 + 19 seconds

Answer 5

Velocity = (final distance - initial distance)/time
=(0-0)/(15+19)
=0

Answer 6

strictly speaking , in classical mechanics the formula i gave you is for the average SPEED
which is independent of the direction, whereas velocity has both speed and direction.

Answer 7

mathmate has it

Answer 8

@mathmate Joe is on a cross-country trip from New York to Los Angeles. He drives for 45.0 min at 70.0 km/h, 10.0 min at 95 km/h, and 30.0 min at 55.0 km/h, and he spends 20.0 min eating lunch and buying gas. What is the average speed for this part of his trip?
a.
67.6 km/h
c.
54.7 km/h
b.
68.4 km/h
d.
53.8 km/h

Answer 9

@patdistheman Two cars drive in the same direction along a straight road, at a constant speed - one at 70 km/hr and the other at 80 km/hr. Assuming that they start at the same point and at the same time, how much sooner would the faster car arrive at a destination 460 km away?
a.
49 minutes
c.
5.75 hrs
b.
6.6 hrs
d.
741 minutes

Answer 10

I do not see how this can be 0.

A swimmer travels from the south end to the north end of a 30.0 m pool in 15.0 s and makes the return trip to the starting position in 19.0 s. What is the average velocity for the roundtrip?
a.
2.50 m/s to the south
c.
2.50 m/s to the north
b.
2.27 m/s to the north
d.
0.0 m/s

Answer 11

is it c @patdistheman

Answer 12

A total distance of 60 meters is traveled in 34 seconds it would seem the average velocity would be (60/34) = 1.765 m/s.

Answer 13

@mathmate Joe is on a cross-country trip from New York to Los Angeles. He drives for 45.0 min at 70.0 km/h, 10.0 min at 95 km/h, and 30.0 min at 55.0 km/h, and he spends 20.0 min eating lunch and buying gas. What is the average speed for this part of his trip?
a.
67.6 km/h
c.
54.7 km/h
b.
68.4 km/h
d.
53.8 km/h

What you would do is to tabulate the time and distances.

Average speed = total distance/total time = 95.8333/1.75 hr. = 54.76 km/hr