Can someone please help? Much appreciated <3
Solve for x and y such that ABCD is a parallelogram.
Really Big Hint: Oppostive Angles are Congruent.
So the answer is 3y-20?
No. Can you identify Opposite angles? \(4x = 4y + 4\) You show me the other one.
2x + 6 = 3y - 20?
Perfect. We have: \(4x = 4y+4\) \(2x + 6 = 3y - 20\) Having said that, we can abandon the geometry and work with the algebra problem. Can you solve this system of equations?
6x + 6 = 7y - 20?
I'll take that as a "no". You should have studied several methods to solve such systems. "Substitution" "Matrix Inverse" "Equation Addition" "Determinants" Maybe you haven't heard of all of those. Any sound familiar?
no haha
Well, that's bad, but you did seem to want to add he two equations, so let's figure out how to get that method to do somehting for us. First, rearrange to a consistent form. I'll do the first one. 4x=4y+4 can be written as \(4x - 4y = 4\) You write the other one in a consistent format. x first, then y then = soem constant.
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