Question

Factor:
x^3-9x

Answer 1

\[x(x^2-9)\] is a start. then factor the \(x^2-9\) part as the difference of two squares

Answer 2

wait im confused, can you show work?

Answer 3

He just took out an x

Answer 4

so x(x^2-9) is the answer?

Answer 5

\[x^3-9x\]
x is common to both sides

Answer 6

so then \[x(x^2-9)\]

Answer 7

ohh okay

Answer 8

But \[x^2-9 is factorable\]

Answer 9

how do you factor x^2-9 though?

Answer 10

Use the rule of a difference of two squares.

Answer 11

\[(x+3)(x-3)\]

Answer 12

oh okay i understand, i was just confused at how you were explaining it, thanks