In a dog show, 20% of the dogs are eliminated each day. If the competition starts with 2,000 dogs, to the nearest integer, how many dogs will be present at the start of the 5th day?

Question

anonymous · Answer

Since 20% = .2, multiply 2000 by .2 five times. Like so,

2000*.2

But do this 5 times, and you minis well say 2000 * (.5)^5

anonymous · Answer

And then round down

anonymous · Answer

WOOPS! Take 2000 - (2000*(.2)^5)

anonymous · Answer

i got 480 as my answer.

anonymous · Answer

I got 655, but I may have messed up.

anonymous · Answer

hmmm

anonymous · Answer

@nickjesus3 i think you may have lol! :)

anonymous · Answer

oh i read it wrong.
just want $2000\times .8^5$

anonymous · Answer

Yeah, I definitely messed up this one... Perhaps 480 is correct

anonymous · Answer

Its okay i think im right lol but im still not sure !!

anonymous · Answer

20% decrease every day means 80% remain

anonymous · Answer

655 looks good to me

anonymous · Answer

my study guide only shows the answer choices of 259

480

819

1,229

anonymous · Answer

Yeah, after I realized the equations I put up were wrong I manually did 2000-(2000*.2) = 1600 - (1600*.2) = 1280 - (1280*.2) =....=655

anonymous · Answer

@satellite73

anonymous · Answer

hmmmmm.... i wonder whats wrong lol it must be the study guide!! lol or idk what it is

anonymous · Answer

@hero do you see what the problem is??

hero · Answer

I'm pretty sure @satellite73 is correct.

anonymous · Answer

yeah so am i

hero · Answer

But I think the question wants $$2000 \times .8^4$$

anonymous · Answer

ah so it does!!

anonymous · Answer

is 819 a possibility?

anonymous · Answer

yes @satellite73