can i algebra help with this?
you have to solve for x by cross multiplying i think
You could write the left hand side as one fraction, but maybe it is easier to just multiply everything with 6:\[6 \cdot \frac{ x+3 }{ x+5 }+x=5\]Now there ins only one fraction instead of three ;)
To get rid of the last fraction, multiply everything with x+5:\[6(x+3)+x(x+5)=5(x+5)\]This is beginning to look good!
Work out the brackets, put everything on the left hand side and add up where possible. You now have a quadractic equation. You can solve it.
One warning, however: In the original equation you can see that x cannot be -5 (division by 0). After the fractions are all gone, you can't see that anymore. It could even have "solution" -5. If that occurs, you should discard it (because you were looking for the solution of the first equation - with fractions).
@lamborghini69 I hope this is quite clear ?
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