determine the ratio of the area of the outer regular pentagon to the area of the shaded inner region
1/10th
which grade are you in?
what you can do is assume the length of a side of the pentagon as 5, then bruteforce the solution
11th
idk what you said in the second comment means??
but how? can you explain how you got it please?
ok so.. first what is the angle of each corner of pentagon
i dont know it dosent say anything about it ?
a pentagon has 540 degree as inner angle, hence each corner has 540/5=108 degree
ohhh :O im sorry i feel so stupid :/
the final answer is 6.85
tell me if you wanna know how to do it
yes i do :O
easier to explain here: https://docs.google.com/drawings/d/1Ez2TDLcr-tM2E6ye-ptQ5KAmy2sSIsTtmYVZ2VQrhJE/edit
ok
do you get it now...
no -___________________________-
Let me give it a try? All you need to do to find the answer to this problem is find the ratio between the lengths of the sides of the pentagon. The ratio of the areas of the pentagons is the ratio of the lengths, squared. If this sounds complicated, think of a square. For a square with a side length of four, the length is four times that of a square with a length of 1, and the area is 16 times that of a square with a length of 1. Okay, now that that's out of the way, we can take a look at our pentagon:|dw:1357514712589:dw| To find the ratio of s2 to s, we can find the following ratio:|dw:1357514938310:dw| Because the pentagon is a regular pentagon, we already know the external angles (shown in the first picture). So, L1 = s * sin(36) = 0.588s. L2 = s * sin (72) = 0.951s. L1 : L1 + L2 = 0.588 : 0.588 + 0.951 = 0.382 So, the ratio of the sides of the two pentagons is 0.382. This means that the area ratio squared is (0.382)^2 = 0.146 The ratio of the outer pentagon to the inner pentagon is 1 / 0.146, or 6.85. I can see why this would be a difficult question. If you have any questions, please ask!
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