Question

how do you factor and solve the equation
50x^4-32=0 ??

Answer 1

well start by taking out 2 as a common factor

\[2(25x^4 - 16) = 0\]

this is now an equation that is reducible to a quadratic

let \[x^2 = u\]

so you have

\[2(25u^2 - 16) = 0\]

this is the difference of 2 squares... which can be factorised...

are you able to do this...?