Question

Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2).
Answer

y = 5x + 2

y = -2/5x + 2

y = 2x + 5

y = 1/2x + 5

Answer 1

Well it is easy

First of all find the slope of the equation :)

Answer 2

perpendicular is opposite reciprical

Answer 3

pourquoi tu n'as pas de cerveau serieux mon dieu..

Answer 4

so how do i find slope with the y=mx+b right?

Answer 5

Yeah

Answer 6

what is the slope so far?

Answer 7

5/2?

Answer 8

We will find the slope of this equation and use

\[\huge\ m_1 \times m_2=-1\]

Answer 9

So we can find the slope of the line perp to it.

Answer 10

now what is the opposite reciprical of 5/2?

Answer 11

2/5

Answer 12

-2/5 *

Answer 13

oh so now I?

Answer 14

Now use,

y-y1=m(x-x1)

Answer 15

yes -2/5 i say opposite because if the slope was positive the opposite would be negative. n so forth

Answer 16

Use the formula i provided :)

Answer 17

\[m_2=-1/m_1\]

Answer 18

so id do the same with this formula like id did the other 1 earlier?

Answer 19

Yes :)

Answer 20

with the 2 ys and 2 xs that was confusing to me??

Answer 21

Play the plug in game ;)

Answer 22

I am off to sleep @blondie16 will take care of the rest i guess if you need help.

Answer 23

okay thank you for your help @hba

Answer 24

so ampy id just get y-2=-2/5(x-5/2)??

Answer 25

no x1-0

Answer 26

oh okay

Answer 27

y-y1=m(x-x1) then plug in the y value into the y1 and the x value into the x1 and the new slope into m

Answer 28

so it would be y-2=-2/5(x-0)?

Answer 29

other way around xD

Answer 30

-2/5(x-0)=y-2?

Answer 31

LOL switch the x and y values

Answer 32

y-0=-2/5(x-2) ??

Answer 33

yesh then solve for y... but the answer is pretty easy bc there is only 1 answer with the same slope

Answer 34

thanks