Question

Use the general power rule to evaluate the integral:

Answer 1

\[\int\limits_{}^{}x \sqrt{8-4x ^{2}} dx\]

Answer 2

if you see properly, if you let whole of what is inside the sq. root , as t ,
then a very easy expression to integrate shall come into play..

Answer 3

i know just the general way of solving it in which u have to substitute
\[4x ^{2}=t\]
differentiate both sides wrt to x
8x=dt/dx
(8x)dx=dt
the integral after substitution changes to
\[(1/8)\int\limits_{}^{}\sqrt{8-t}dt\]

Answer 4

ok! remember to close the question guys and if appropriate, to award medals:)