Question

PLEASE HELP
Find the derivative of:
(well its equation of tangent line but the derivative is complex)
http://imgur.com/NMRNI
@satellite73
@jim_thompson5910

Answer 1

start by taking the log

Answer 2

@satellite73 hi again, sorry to bother you, but when you are finished here could you possibly help me again? thanks so much

Answer 3

\[\ln(y)=\frac{1}{x}\ln(8x)\] take the derivative of that one

Answer 4

then multiply back by the original function

Answer 5

\[\frac{d}{dx}\ln(y)=\frac{1}{x^2}-\frac{\ln(8x)}{x^2}\] i think, please check it

Answer 6

or if you prefer \[\frac{1-\ln(x)}{x^2}\] then multiply by \(8x^{\frac{1}{x}}\) for your derivative

Answer 7

alright I've tried to get this problem right so many times. i still cant get it.

so y'=(8x^(1/x))((8-lnx)/(x^2))

this is our slope correct?
(y-8)=m(x-1)

when i put in m- i still get the wrong answer