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Mathematics 21 Online
OpenStudy (anonymous):

can someone please help!!

OpenStudy (anonymous):

can you please explian how to rewrite an equation in vertex form

OpenStudy (anonymous):

you mean like a quadratic equation?

OpenStudy (anonymous):

Post an actual problem. Easier to explain that way

OpenStudy (anonymous):

yes i mean quadratic equation @binarymimic ... y=x^2 - 6x=4 @chaguanas

OpenStudy (anonymous):

y = x^2 - 6x - 4 ?

OpenStudy (anonymous):

its one of the problems i need help with .....

OpenStudy (anonymous):

you wrote "y = x^2 - 6x = 4" but did you mean "y = x^2 - 6x - 4 "

OpenStudy (anonymous):

oh sorry its +4

OpenStudy (anonymous):

y = x^2 - 6x + 4 to write it in vertex form you have to complete the square. have you done that before ?

OpenStudy (anonymous):

Do you know how to do that thing called 'completing the square'?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

keep x^2 - 6x on one side,and everything else on the other so you have: x^2 - 6x = y - 4 this just makes the process clear then you take -6 divided by 2 = -3 take -3 and square it = 9 so add 9 to both sides x^2 - 6x + 9 = y - 4 + 9 the left side factors now into (x - 3)^2 = y + 5 then subtract 5 back to the left side (x - 3)^2 - 5 = y

OpenStudy (anonymous):

some info on how to complete the square: http://www.regentsprep.org/Regents/math/algtrig/ATE12/completesqlesson.htm

OpenStudy (anonymous):

so would that be the answer? or do i have to do more

OpenStudy (anonymous):

y = (x - 3)^2 - 5 is the vertex form

OpenStudy (anonymous):

okay thanks ....

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