Find the missing terms of the arithmetic sequence 4______ 22 25______,53_______
@ganeshie8
Hmm, lets call the missing term x, the difference between a number and the previous one is always the same in an arithmetic sequence. 4,x,22 so x-4 should be the same as 22-x do you follow?
ehhh not really but some how i got 18
Thats not right =p say you have the arithmetic sequence 2,4,6,8 8-6=2 6-4=2 4-2=2 so the difference is always the same so in 4,x,22 22-x is the same as x-4 therefore 22-x=x-4 solve for x
whaai don't get it lol it just more confusing
how do you solve for x
Basic algebra add x to both sides 22=2x-4 add 4 to both sides 26=2x divide both sides by 2 13=x
so 13 would be the answer for the first one and how did you get 2x
i added x to both sides of the equation x+x is 2x
ok so is that the answer and do i do the same for the next question
yes 13 is the answer same idea for the second one, can you try?
ok and i was gonna try but then its more than two numbers, what now? :O
just worry about the first blank for now. pretend its 25,x,53
i got -39 , this is what i did am not sure but 25=2x-53 then divide -78 over 2 which is how i get -39
you do 53-x=x-25
omg can you help me with that..?
Add x to both sides first
yea and i got 53=2x-25
thats right, now add 25 to both sides
i did and overall i got 39
Thats right, thats the first blank
yayy ok, so how is the next one done?
For that one you can just use the difference, you now have 25,39,53 14 is being added each time, 53+14=?
which would be 67
Right =D
yayy thank you..
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