Question

What is the equation of the line that passes through the point (2, 3) and is perpendicular to the line y = –x – 3?

y = –x – 1

y = –x + 5

y = x + 1

y = x + 5

Answer 1

how do i do this

Answer 2

First thing, do you know the slope of y=-x-3?

Answer 3

no how do i get it

Answer 4

its already in the form

y=mx+b

where m is the slope, so the coefficient of x is the slope

Answer 5

so the slope is -1?

Answer 6

Yep, a line perpendicular to that would have the negative reciprocal of its slope.

so slope of the line you're trying to find is 1

use point slope form now

y-y1=m(x-x1)

Answer 7

wait what do you mean use point slope now ?

Answer 8

@CalebBeavers

Answer 9

point slope form

y-y1=m(x-x1)

(x1,y1) is the point you have (2,3)

and m is the slope, 1

plug those in