Quick question about derivatives involving Newton's dot notation and the chain rule:

I was just wondering if, say you have a velocity function in terms of t, would that be considered x-dot?

So for example, if they give x=2t and that's in terms of velocity, it's x-dot? And then the derivative of that for acceleration would be x-double dot?

Furthermore, say you have a velocity position function y=x^2. Would the chain rule for that be y = 2x*(x-dot)?

If you're confused by when I say x-dot, I'm talking about this:
http://web.mst.edu/~reflori/be150/Dyn%20Lecture%20Videos/Particle%20Kinem%20x-y%20Coords%201.pdf

Question

Quick question about derivatives involving Newton's dot notation and the chain rule:

I was just wondering if, say you have a velocity function in terms of t, would that be considered x-dot?

So for example, if they give x=2t and that's in terms of velocity, it's x-dot?  And then the derivative of that for acceleration would be x-double dot?

Furthermore, say you have a velocity position function y=x^2.  Would the chain rule for that be y = 2x*(x-dot)?

If you're confused by when I say x-dot, I'm talking about this:
http://web.mst.edu/~reflori/be150/Dyn%20Lecture%20Videos/Particle%20Kinem%20x-y%20Coords%201.pdf

anonymous · Answer

@No-data