i need biiig help ! i will post question when someone willing is going to help. it looks like a long thing but its really not. the actual question is short. anyone up for the challenge ?
ill help
Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? Salisbury High School decided to take their students on a field trip to a theme park. A total of 150 people went on the trip. Adults pay $45.00 for a ticket and students pay $28.50 for a ticket. How many students and how many adults went to the park if they paid a total of $4770? Your piggy bank has a total of 46 coins in it; some are dimes and some are quarters. If you have a total of $7.00, how many quarters and how many dimes do you have? Follow the 5 steps below to complete this problem. Step 1 Pick a friend or family member to be the character of your word problem. This friend or family member may do one of the following: Drive a boat [[Drive a jet ski]] Step 2: Select a current speed of the water in mph. 50 mph Step 3: Select the number of hours that your friend or family member drove the boat or jets ski against the current speed you chose in step 2. 1 hour Step 4: Select the number of hours that your friend or family member made the same trip with the current (this should be a smaller number, as your friend or family member will be traveling with the current). 40 mph Step 5: Write out the word problem you created and calculate how fast your friend or family member was traveling in still water. Round your answer to the nearest mph.
you should post one at a time, il address the first one. Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? let x be tonys age, and y be belindas age, so their combined ages: (1) x+y=56 and belinda is 8 more than twice his age meaning: (2) y=2x +8 now isolate in equation (1), isolate either variable, i chose x: x=56-y substitute it into (2) y=2(56-y)+8 solve for y (belindas age), then knowing y, find x using any of the previous equations ie. (1) or (2)
okay i was with ya until the last part. are u asking me to tell u the answer, 1 or 2, or is that the rest of it ? and yeaa sorry im in a hurry and didnt think of that.
they're asking you for their ages, so y will be belindas age and x will be tonys. solve for y, y=2(56-y)+8 then plug y into (1) x+y=56 or (2) y=2x +8 (so that you only have one unknown) then find x
@aaronq ????
they're asking you for their ages, so y will be belindas age and x will be tonys. solve for y, y=2(56-y)+8 then plug y into (1) x+y=56 or (2) y=2x +8 (so that you only have one unknown) then find x
i set it up for ya, but haven't solved for the answer thats your job
okay but idk how to plug in y. ill plug it into (1) can u tell me how and ill do it and tell u what i get ?
solve for y, it will be a number, lets say 4 (this is an example not the answer) then plug it into (1) x+4 =56, find x
i dont know how. -___- do i multiply ? add ? divide ? what ?
you don't know how to solve this y=2(56-y)+8?
not at all. sorry.
do i use pemdas ?
yes
i got y = 120
lol do you think belinda is 120 years old? hint: their ages have to add up to 56, remember? haha y=2(56-y)+8 expand bracket y=112-2y+8 bring 2y to other side 2y+y=112+8 add up y's and number 3y=120 isolate y y=120/3 y=40
oh im a fail :/
haha it's okay, you just gotta practise
i will. so is there more to do ?
yep, since you know the value of y, you can use it in any of the previous equations to find x. (1) x+y=56 x+40=56 what is x?
x+40=56
yes, solve for x
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