Question

How would I solve this?
(a/b+1/a) (a-(a3)/(a2-b))

Answer 1

one of those is the answer

Answer 2

So, solve what's in the parentheses first, then multiply them.

Answer 3

What exactly are you having trouble with?

Answer 4

So the first parentheses is (a2+b)/(ab) and the second one is (-ab)/(a2-b) ?

Answer 5

One second

Answer 6

Now, subtract the a^3 and you'll have ab. So, \[equation1(\frac{ a ^{2}+b }{ ab}) (\frac{ ab }{ a ^{2}+b })equation2\]
Now, notice that equation 1 has as its denominator ab, and equation 2 has as its numerator ab.... cross them out and replace them with 1 :D \[equation1(\frac{ a ^{2}+b }{ 1})(\frac{ 1}{a ^{2}+b})\]
Which, equals \[\frac{ a ^{2}+b }{ a ^{2}+b}\]
=1!

Answer 7

Thank you!