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How would I solve this? (a/b+1/a) (a-(a3)/(a2-b))
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one of those is the answer
So, solve what's in the parentheses first, then multiply them.
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So the first parentheses is (a2+b)/(ab) and the second one is (-ab)/(a2-b) ?
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|dw:1357796129588:dw|
Now, subtract the a^3 and you'll have ab. So, \[equation1(\frac{ a ^{2}+b }{ ab}) (\frac{ ab }{ a ^{2}+b })equation2\] Now, notice that equation 1 has as its denominator ab, and equation 2 has as its numerator ab.... cross them out and replace them with 1 :D \[equation1(\frac{ a ^{2}+b }{ 1})(\frac{ 1}{a ^{2}+b})\] Which, equals \[\frac{ a ^{2}+b }{ a ^{2}+b}\] =1!
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