Question

6 blue, 5 red and 4 green balls are arranged so that no 2 of the red balls are together. in how many ways can this be done if all balls of the same color are indistinguishable.

Answer 1

answer key says 97020 O: i didn't get it though...
i tried doing
15! over 5!6!4! - 11!over 6!4! O: O:

Answer 2

I don't get that answer either. I got a lower number then that

Answer 3

heeelp?? @ParthKohli ?@Hero @ash1122

Answer 4

I'm no good at combinatrics since I'm still at it's early stages of learning, but do you have the correct answer?

Answer 5

since each ball of the same colour is same
first arrange 6 blue and 4 green balls which can be done in 10!/(6!*4!)
now in between these there are 11 spaces which is to be filled with 5 red balls
which can be done in (11*10*9*8*7)/5! ways =462

hence the required no of ways must be 10!/(6!*4!) *462=210*462=97020
(for calculation u may check once more )

Answer 6

WOW THANK YOU!!!!!!! THANK YOUU!! <3

Answer 7

welcome dear