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If 2 +squarerootof 3 is a polynomial root, name another root of the polynomial and explain how you know it must also be a root
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no
Seen the quadratic formula?
its -2-root3.. See the polynomial is going to be 2+root3 multiplied by itself and the product of it is going to have two square roots of which -2-root3 is one of them
Look how it says that if \(s\) and \(r\) are roots, then\[s = \frac{-b + \sqrt{b^2 - 4ac}}{2a}\]and\[r = \frac{-b - \sqrt{b^2 - 4ac}}{2a}\]
So what would happen if we take \(s = 2 + \sqrt{3}\)?
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@ Parth it says polynomial not quadtraic
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