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OpenStudy (anonymous):
Definite integrals: Check my work
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OpenStudy (cgreenwade2000):
Ready when you are
OpenStudy (anonymous):
My answer is 2/3
OpenStudy (cgreenwade2000):
I get 1/6 What steps did you take to solve this?
OpenStudy (anonymous):
I converted the equation to x^-2, then took the integral to get (x^-1)/1 . I plugged 3 and 1 and got -1/3 - -1/1. That translated to 2/3.
OpenStudy (cgreenwade2000):
How did you convert x^2/(x^3 + 1)^2 into x^-2? There should be some substitution in there.
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OpenStudy (anonymous):
ohh...I see what happened. I posted the wrong problem!
OpenStudy (cgreenwade2000):
let u = x^3+1 Then du=3x^2 dx Which would give you
OpenStudy (cgreenwade2000):
ok
OpenStudy (anonymous):
OpenStudy (cgreenwade2000):
2/3 is correct then
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OpenStudy (anonymous):
Thanks! Was my process good?
OpenStudy (cgreenwade2000):
yes
OpenStudy (anonymous):
Would you check my work for the mistakenly posted problem?
OpenStudy (cgreenwade2000):
yes go for it
OpenStudy (cgreenwade2000):
Actually, post a new problem and Ill help you there
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