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Mathematics 6 Online
OpenStudy (anonymous):

Definite integrals: Check my work

OpenStudy (cgreenwade2000):

Ready when you are

OpenStudy (anonymous):

My answer is 2/3

OpenStudy (cgreenwade2000):

I get 1/6 What steps did you take to solve this?

OpenStudy (anonymous):

I converted the equation to x^-2, then took the integral to get (x^-1)/1 . I plugged 3 and 1 and got -1/3 - -1/1. That translated to 2/3.

OpenStudy (cgreenwade2000):

How did you convert x^2/(x^3 + 1)^2 into x^-2? There should be some substitution in there.

OpenStudy (anonymous):

ohh...I see what happened. I posted the wrong problem!

OpenStudy (cgreenwade2000):

let u = x^3+1 Then du=3x^2 dx Which would give you

OpenStudy (cgreenwade2000):

ok

OpenStudy (anonymous):

OpenStudy (cgreenwade2000):

2/3 is correct then

OpenStudy (anonymous):

Thanks! Was my process good?

OpenStudy (cgreenwade2000):

yes

OpenStudy (anonymous):

Would you check my work for the mistakenly posted problem?

OpenStudy (cgreenwade2000):

yes go for it

OpenStudy (cgreenwade2000):

Actually, post a new problem and Ill help you there

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