Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, -3)
A
B
C.y = 2x – 21
D
@blondie16
first solve that equation for y and tell me what you get
thts the thing i dont know how to do it
2x + 3y = 5 first you would sutract the 2x -2x -2x 3y=-2x+5 then you would divide by 3 _______ 3 3 3 so it would = y=-2/3x+5/3
i get it thx i luv u (u know wat i mean)
lol but your not done with the question! do you get the rest?
the rest are awnsers like abcd u know
but your not finished with the questions you have to find the perpendicular slope to the slope you got. and you have to put it through the point (9,-3)
ohhh
so i have to plug them it in right
lol yep :P to find the perpendicular slope you have to find the opposite reciprocal do you know how to do that?
and no dont plug them in
ohh thn how?
well we found out that the slope of that line was -2/3 right? so the 'opposite' of that would be positive and the reciprocal would be 3/2 so that is the new slope: 3/2(m). now for the new point. (9(x1),-3(y1)), plug it in to the equation : y-y1=m(x-x1) the 9 goes into the x1 spot and the -3 goes into the y1 spot. dont forget, the y1 is a negative 3 and in the equation, it subtracts it so the 3 would become positive.
ohh isn tht point slope form
yesh it is :)
i get it thx
yay :D your welcome glad i could help reaper :P
:D
swear i learn more here then on my school
oops! i read perpendicular :O it is parallel :( so it would still be -2/3 sorry i misread that and lol
its ok
alright so if you want me to check it i will if you want haha
thx
welcome :)
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