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Verify the identity. cos 4x + cos 2x = 2 – 2 sin^2 2x – 2 sin^2 x
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cos4x = cos2(2x) = 1 - 2sin^2 2x cos2x = 1 - 2sin^2 x just joining the sum of them
Is that the answer?
exactly, yeah... :)
Okay, thank you. Do you mind helping me with another question? :o)
cos4x + cos2x = 1 - 2sin^2 2x + 1 - 2sin^2 x = 2 - 2sin^2 2x - 2sin^2 x LHS = RHS
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i'll try
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. \[f(x)=\frac{ x-7 }{ x+3 }\]\[g(x)=\frac{ -3x-7 }{ x-1 }\]
@RadEn Do you know how to do this?
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