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OpenStudy (dls):
A line passing through (2,2) is perpendicular to the line 3x+2y=3.its y intercept is?
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OpenStudy (anonymous):
Since the Lines are perpendicular m 1 * m2 = -1
OpenStudy (dls):
m=2/3
OpenStudy (dls):
kthx
OpenStudy (anonymous):
3x+2y=3
3x + 2y - 3 =0
m1 = -a/b = -3/2
m2 = 2/3
Nw use Point Slope Form
OpenStudy (anonymous):
y-y1 = m(x-x1)
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OpenStudy (anonymous):
Hope nw u can Solve it
OpenStudy (dls):
3y-2x-2=0
OpenStudy (dls):
i got till here before too..im gettig 2/3..itswrrong
OpenStudy (anonymous):
(2,2) y-y1 = m(x-x1)
y-2 = 2/3 ( x-2)
3y - 6 = 2x - 4
2x - 3y +2=0
OpenStudy (anonymous):
Nw to Find y intercept.....Put x = 0
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OpenStudy (dls):
IM GETTING 2/3 ITS WRONG:/
OpenStudy (anonymous):
So
-3y = -2
y = 2/3
OpenStudy (dls):
WRONG
OpenStudy (anonymous):
But that Shuld be it.....Can u Check ur Question and Answer Key Once Agian ?
OpenStudy (dls):
4/3..
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OpenStudy (anonymous):
hm..hm..
OpenStudy (anonymous):
Are you 100% sure you copied the correct equation and point? If not, then @Yahoo! is spot on.
OpenStudy (dls):
yes..i just want to confirm is there any hope of getting 4/3 or is there defintely a misprint in my ans key..
OpenStudy (anonymous):
Read the second part of my comment. It already states that if it is the correct equation and point, then it's a typo/misprint.
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