A line passing through (2,2) is perpendicular to the line 3x+2y=3.its y intercept is?
Since the Lines are perpendicular m 1 * m2 = -1
m=2/3
kthx
3x+2y=3 3x + 2y - 3 =0 m1 = -a/b = -3/2 m2 = 2/3 Nw use Point Slope Form
y-y1 = m(x-x1)
Hope nw u can Solve it
3y-2x-2=0
i got till here before too..im gettig 2/3..itswrrong
(2,2) y-y1 = m(x-x1) y-2 = 2/3 ( x-2) 3y - 6 = 2x - 4 2x - 3y +2=0
Nw to Find y intercept.....Put x = 0
IM GETTING 2/3 ITS WRONG:/
So -3y = -2 y = 2/3
WRONG
But that Shuld be it.....Can u Check ur Question and Answer Key Once Agian ?
4/3..
hm..hm..
Are you 100% sure you copied the correct equation and point? If not, then @Yahoo! is spot on.
yes..i just want to confirm is there any hope of getting 4/3 or is there defintely a misprint in my ans key..
Read the second part of my comment. It already states that if it is the correct equation and point, then it's a typo/misprint.
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