Question

please help! :) Write in standard form: y²+4y-8x+4=0

Answer 1

wait :)

Answer 2

\[\large{ y²+4y-8x+4=0}\]\[\large{=>y^2+4y-8x=-4}\]

Answer 3

got it??

Answer 4

thanks! is that standard form? somebody else told me this: 8x=(y+2)²
which is correct? @TheViper

Answer 5

mine :)
well I wanna check because I just understand to write an equation in standard form :)

@ash2326 plz help :)

Answer 6

@Hero :)

Answer 7

Can u tell me I did write or wrong ??

Answer 8

\[(y+2)^2 - 8x = 0\]

Answer 9

Yes I did not solve that further :)
So @erin512 @Hero is correct :)
Sure ;)

Answer 10

Got it ?

Answer 11

@Hero hates math in picture otherwise he loves math :D

Answer 12

@Hero @TheViper thank you so much :)

Answer 13

yw :)