NEED HELP GEOMETRY!
Two similar rectangles have lengths 18 in and 12 in. What is the ratio of their widths? What is the ratio of their perimeters?
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OpenStudy (anonymous):
The ratio of their widths will be the same as the ratio of their lengths:
L1/L2 = 18/12 = 3/2
The ratio of their perimeters will also be:
3/2
because (2L1 + 2W1)/(2L2 + 2W2) = (L1 + W1)/(L2 + W2)
OpenStudy (anonymous):
would the area be the same ratio?
OpenStudy (anonymous):
@tcarroll010
OpenStudy (anonymous):
no
OpenStudy (anonymous):
@tcarroll010 hi! can you pleasee help me when you are done here?
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OpenStudy (anonymous):
sure @erin512
OpenStudy (anonymous):
how would i find it out?
OpenStudy (anonymous):
The ratio of the areas is 9/4 which is (3/2)^2
OpenStudy (anonymous):
thanks so much :)
OpenStudy (anonymous):
why would you square it?
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OpenStudy (anonymous):
First area is LW, the second area is [(3/2)L] x [(3/2)W] = (9/4) of the first area.
Yiou square it because both the length and width are 3/2 bigger.