Question

Solve for x:
log2(x−4)log2(x−3)=1

Answer 1

\[\log_2(x−4)\log_2(x−3)=1\]Is this the correct problem?

Answer 2

ah, I got it. I forgot this law. Thank you! :)

Answer 3

I don't see how that solves the question.

(x -4)(x - 3) = 2 would give x = 2 or 5.

Substitute 2 or 5 into the original equation doesn't give 1. Am I doing something wrong here?

Anyway how can you raise each term like this?
\[ a * b = c \rightarrow 2^{a} * 2^{b} = 2^{c}\]since \[2^{a} * 2^{b} = 2^{c} \rightarrow 2^{a + b} = 2^{c} \rightarrow a+b = c\]