Question

Find the polar form of the equation x^2+y^2=10y

Answer 1

Okay so the easiest part is: \[
r^2 = x^2 + y^2
\]So we get it like this: \[
r^2=10y
\]Next we use: \[
y = r\sin\theta
\]To get: \[
r^2 = 10r\sin\theta
\]Lastly dividing by \(r\) we get: \[
r = 10\sin\theta
\]

Answer 2

The choices are:
A. (r=\[\sqrt{10 \sin \theta}\]
B. r= 10 sin theta
C. r= 100sin^2 theta
D. None of the above

Answer 3

Just use the following equations: \[
\begin{array}{rcl}
r^2 &=& x^2+y^2 \\
x &=& r\sin\theta \\
y &=& r \cos\theta
\end{array}
\]

Answer 4

I already pretty much gave you an answer on a platter, I'm not picking out a letter. Try to think about the problem a bit.

Answer 5

Okay I got it thanks

Answer 6

oops, I swapped the \(x\) and \(y\) on those equations above.
stupid open study thing doesn't let you edit.

Answer 7

For the record \[
\begin{array}{rcl}
r^2 &=& x^2+y^2 \\
y &=& r\sin\theta \\
x &=& r \cos\theta
\end{array}
\]

Answer 8

Thanks I will keep all of those equations in mind