Can someone answer this question for me please. i just need the answers... Solve. x^2 + 5x + 3 = 0
Hi, welcome... but the site doesn't allow you to get answers. I will help you out if you need it. :-)
You have to compare your equation with the standard form of quad equation and determine a,b and c. \[\huge\ ax^2+bc+c=0\] After you are done with that use the Quad formula, \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Heard about the quadratic formula? :-)
There are two other methods you can use: 1)Breaking the middle term 2)Completing the square method.
yes. but i don't understand how to solve this
Do you see what all i have written up.
i see it @ hba
@keshab1234 So what is a,b and c ?
1x^2 + 5x + 3 = 0 compare with ax^2+bx+c=0 a,b and c=
I'd probably rephrase it, and ask: What are the coefficients?
@ParthKohli Ye Americion ki dimaag mai kuch nahi jaata :/
coefficients are substitutes for the actual number
He asked what are the coefficients in your equation.
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