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Mathematics 14 Online
OpenStudy (anonymous):

Solve and check. 2x+3 > 17

OpenStudy (ksaimouli):

x>7

OpenStudy (ksaimouli):

x>(17-3)/2

OpenStudy (anonymous):

2x+3>17 -3 -3 2x>14 /2 /2 x>7 Check: 2x+3>17 2(7)+3>17 14+3>17 17=17 ✓

OpenStudy (anonymous):

2x+3>17 -3 -3 ______________ 2x/2 > 14/2 x=7 2(7)+3 > 17 14+3 > 17 17 > 17 is that true?

OpenStudy (anonymous):

opps 17=17 HA

OpenStudy (anonymous):

thanks !

OpenStudy (anonymous):

what about 2x/3 - 1/2 < 3/2

OpenStudy (anonymous):

No prob

OpenStudy (anonymous):

\[2x+3>1\] now -3 both sides \[2x+3-3>1-3\] then divide both sides in 2\[x>7\].. if we choose any number major to 7 (for example 8) we have \[2*8+3>1-->16+3>1-->19>1\]

OpenStudy (anonymous):

sorry \[19>17.. \]

OpenStudy (anonymous):

i lost the 7 lol

OpenStudy (anonymous):

2x/3 - 1/2 < 3/2 +1/2 +1/2 2x/3< 4 *3 *3 2x<12 /2 /2 x<6

OpenStudy (anonymous):

but isn't 3/2 + 1/2 equal to 4/2? which is 2

OpenStudy (anonymous):

2x/3-1/2<3/2 we have to get rid of all the fractions unless you are good with fractions so we mutiply all the fractions by 6 giving us.. 4x-3<9 we mutiply by 6 because it was the LCD (Least Common Denominator) of the fractions. so 4x-3<9 +3 +3 _________________ 4x<12 4x/4<12/4 x< 3 Check 4(3)-3=9 12-3=9 9=9

OpenStudy (anonymous):

@musiclove13 yeah, it's true

OpenStudy (anonymous):

@sheetalvee just remember this chant "WE HATE FRACTIONS!" so whenever you have fractions you must get rid of them by multiplying EVERYTHING by the LCD

OpenStudy (anonymous):

you said multiply everything by 6. so 2x/3 by 6 ? Wouldn't that be 12x/18? How did you get 4?

OpenStudy (anonymous):

Opps, yes sorry.

OpenStudy (anonymous):

soo what would be the correct method?

OpenStudy (anonymous):

you get the fraction 2x/3 then when you mutiply 2/3 by 6 you get 4 so it would be 4x

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