Solve and check. 2x+3 > 17
x>7
x>(17-3)/2
2x+3>17 -3 -3 2x>14 /2 /2 x>7 Check: 2x+3>17 2(7)+3>17 14+3>17 17=17 ✓
2x+3>17 -3 -3 ______________ 2x/2 > 14/2 x=7 2(7)+3 > 17 14+3 > 17 17 > 17 is that true?
opps 17=17 HA
thanks !
what about 2x/3 - 1/2 < 3/2
No prob
\[2x+3>1\] now -3 both sides \[2x+3-3>1-3\] then divide both sides in 2\[x>7\].. if we choose any number major to 7 (for example 8) we have \[2*8+3>1-->16+3>1-->19>1\]
sorry \[19>17.. \]
i lost the 7 lol
2x/3 - 1/2 < 3/2 +1/2 +1/2 2x/3< 4 *3 *3 2x<12 /2 /2 x<6
but isn't 3/2 + 1/2 equal to 4/2? which is 2
2x/3-1/2<3/2 we have to get rid of all the fractions unless you are good with fractions so we mutiply all the fractions by 6 giving us.. 4x-3<9 we mutiply by 6 because it was the LCD (Least Common Denominator) of the fractions. so 4x-3<9 +3 +3 _________________ 4x<12 4x/4<12/4 x< 3 Check 4(3)-3=9 12-3=9 9=9
@musiclove13 yeah, it's true
@sheetalvee just remember this chant "WE HATE FRACTIONS!" so whenever you have fractions you must get rid of them by multiplying EVERYTHING by the LCD
you said multiply everything by 6. so 2x/3 by 6 ? Wouldn't that be 12x/18? How did you get 4?
Opps, yes sorry.
soo what would be the correct method?
you get the fraction 2x/3 then when you mutiply 2/3 by 6 you get 4 so it would be 4x
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