The length of a side and a diagonal of a rhombus are 5cm and 8cm respectively. Find the area of the rhombus?
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|dw:1358060123042:dw| In a rhombus, the diagonals are perpendicular bisectors.
As we know that the halves of diagonals and a side of a rhombus from a right angled triangle with side as hypotenuse. Let the length of the other diagonal =2x. ⇒x^2+(8/2)2= 52 ⇒x^2+16=25 ⇒x^2=25-16 ⇒x^2=9 ⇒x=3 The measure of the another diagonal of the rhombus = 2×3 = 6 cm ∴Area of the rhombus = (1/2)×Diagonal of a rhombus×Measure of the another diagonal ⇒Area of the rhombus = (1/2) ×8×6=24 cm^2
Did i do the sum correct or not.
Be careful how you write in your equations... you have 5^2 written as 52, and (8/2)^2 written as (8/2)2. But yes, your working looks correct.
yup..u r write...
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