very urgent questions:;; please help

An orange solid A on heating gives a colourless gas B .The gas B in dry condition is passed over heated Ca to give a solid C.The solid C further reacts with water to produce gas D which forms a blue coloured compound E on reaction with copper sulphate solution.Identify A,B,C ,D and E and sequence of reactions involved.

Question

very urgent questions:;; please help

An orange solid A on heating gives a colourless gas B .The gas B in dry condition is passed over heated Ca to give a solid C.The solid C  further reacts with water to produce gas D which forms a blue coloured compound E on reaction with copper sulphate solution.Identify A,B,C ,D and E and sequence of reactions involved.

anonymous · Answer

@Callisto @sauravshakya

anonymous · Answer

please please help....

anonymous · Answer

@ParthKohli

hba · Answer

$$(NH_4)_2+Cr_2O7 \ (orange solid- A) $$

hba · Answer

Now heat them so]

(NH4)2+Cr2O7+heat--->

anonymous · Answer

Another question........

A compound A on oxidation gives B($$C _{2}H _{4}O _{2} $$) .A reacts with dilute NaOH and on subsequent heating forms C.C on catalytic hydrogenation gives D.Identufy A,B,C,D and E AND WRITE DOWN THE REACTIONS INVOLVED.

hba · Answer

@nitz The first ques is not yet done.

parthkohli · Answer

Sorry, I don't know chem at all!

andrefontex · Answer

why does he need to stay with the fire more time pointed to the solid, to make it react for itself? . something he couldnt do on 1st and 2nd attempt. http://www.youtube.com/watch?v=mS8CneBEIzI

hba · Answer

For the first one.

shubhamsrg · Answer

here http://www.scribd.com/doc/82528192/Higher-Order-Thinking-Questions page no. 28 question number 7 @hba ;)

hba · Answer

@shubhamsrg I gave her the pdf but she was having a hard time so i snipped it.

hba · Answer

@shubhamsrg My intentions were clear Ahm Ahm :P

shubhamsrg · Answer

Well I didn't say anything, why are you defending yourself! ;)

anonymous · Answer

3rd question::

An organic compound X undergoes acid hydrolysis to form two compounds Y and Z.Y reacts with sodium carbonate to form A.A is heated with soda lime to form B(Methane $$CH _{4}$$)
.Y on reduction with $$LiAlH _{4} $$ forms Z.Identify X,Y and Z.  WRITE THE REACTIONS INVOLVED.

anonymous · Answer

4TH QUESTION:::

An organic compound A  which has characteristic odour on treatment with NaOH forms two compounds B and C.Compound B has molecular formula $$C _{7}H _{8}0$$. Each on oxidation gives back A.The compound C is a sodium salt of an acid.When C is treated with soda lime ,it yields an aromatic hydrocarbon D.Deduce the structures of A,B ,C and D.Write the sequence of reactions involved.

aravindg · Answer

hw many questions are there in total @nitz ?

shubhamsrg · Answer

For 2nd one, C2H4O2 can be CH3COOH
A + NaOH -> CH3COONa + H20

Heating of acetic acid gives CO2
CO2 on catalytic hydrogenation gives methanol

shubhamsrg · Answer

For 3rd one,
X is an ester at first look
on inspection, it is CH3COOC2H5
On hydrolysis, it gives CH3COOH (Y) and C2H5OH(Z)

Then A is clearly CH3COONa

A + (NaOH and CaO) -> CH4 i.e B

We also easily see reduction Y gives Z,

shubhamsrg · Answer

For 4th one,
A is C6H5CHO 
C is C6H5COONa
and B is then C6H5CH2OH 

D is C6H6 clearly.

Hope that is it! phew!
Read almost all my notes to crack these 4 questions. Damn my chemistry is pathetic! :(

shubhamsrg · Answer

For the reaction part :
1st is done
2)CH3COOH + NaOH -> CH3COONa + H20
CH3COOH+heat -> CO2 + CH4
hydrogenation of CO2 -> CH3OH

3)Hydrolysis of X(CH3COOC2H5) ->CH3COOH (Y) + C2H5OH(Z)
 CH3COOH + Na2CO3 -> CH3COONa(A)
CH3COONa + Soda lime(NaOH and CaO) -> CH4(B)

CH3COOH(Y) --reduction with LiAlH4-> C2H5OH(Z)

4)C6H5CHO (A) +NaOH ->C6H5COONa(C) +C6H5CH2OH (B)
C6H5COONa + soda lime ->C6H6 (D)
C -oxidation->A
B-oxidation->A

shubhamsrg · Answer

I never studied/wrote this much for even myself! :O

hba · Answer

lol,I can agree on the above statement :P

anonymous · Answer

An organic compound A has molecular formula $$C _{5}H _{10}0$$.It doesn't reduce Tollen's reagent but forms an orange precipitate with Brady's reagent.It forms a carboxic acid B with molecular formula $$C _{3}H _{6}0_{2}$$ when treated with alkaline $$KMnO _{4}$$,yellow precipitate on treatment with NaOH and $$I _{2}$$.Under vigorous conditions ,on oxidation ,it gives ethanoic acid and propanoic acid.Sodium salt of B gives a hydrocarbon C in Kolbe's electrolyte reduction.Identify A,B,C and write the sequence of reactions involved.

shubhamsrg · Answer

Here, nicely explained http://www.meritnation.com/discuss/question/3570259/0/an-organic-compound-a-has-molecular-formula-c5h10o

anonymous · Answer

@shubhamsrg

shubhamsrg · Answer

Correction in 2nd question
I missed "A" there
so
A must be ethanol since B is acetic acid
CH3CH2OH + NaOH -> CH3CH2ONa(Sodium ethanoate) + H2O

Am confused here. Is A heated alone ? Or its heated after reacting with Naoh?

shubhamsrg · Answer

A  must have been heated
C will remain the same thus
C is CO2

anonymous · Answer

wait

shubhamsrg · Answer

and D is then CH4

anonymous · Answer

thank you @shubhamsrg

shubhamsrg · Answer

Am glad and VERY SURPRISED that I could help in CHEMISTRY ! :D

anonymous · Answer

check the second question

shubhamsrg · Answer

Language of question is not very clear, BUT, its highly probable that aldol condensation is being talked about here since it further gets dehydrated. hmm

shubhamsrg · Answer

A should be then,
CH3CHO
CH3CHO -oxidation-> CH3COOH(B)

now there will be aldol condensation of A

2moles of CH3CHO -NaOH-> CH3CH(OH)CH2CHO +H2O -heating-> CH3CH=CHCHO (C)

hydrogenation(H2/Ni) of C->C4H9OH (D)

andrefontex · Answer

@shubhamsrg can you send me any good links to study it?
i have exam of Organic II next week.

andrefontex · Answer

with those condensed formulas, i can't understand really well

shubhamsrg · Answer

Am really sorry I can't help you much as my organic itself quite bad.
You may though, google over, best of luck .

andrefontex · Answer

ty anyway