identify the x-intercepts in the graph y = 3x2 + 19x – 40.
Hint: Set y = 0
X intercepts are where the function crosses the x axis, where y = 0. Do you know how to solve the equation? \[3x^2+19x-40=0\]
Yeah , you factor out 3 next right?
You can only factor out 3 if the other two coefficients are common multiples of 3, which they are not.
Ok, so then what did you mean by set y=0? Could you explain that a little more?
@whpalmer4 already did it for you.
ooooh! ok Gotcha. ok so then what do I do after that? o.O
Factor the quadratic (if you know how)
As it doesn't look like factoring is going to get you anywhere, try the quadratic formula for the solution. If you have a polynomial \[ax^2+bx+c=0\] the solutions are \[x=-\frac{b\pm\sqrt{b^2-4ac}}{2a}\]
@whpalmer4, it's factorable
You may not have found all the possible factors. You assumed that because 19 is prime, there are no workable factors.
Wasn't saying it wasn't, just that if she didn't say "oh, got this" that she probably wasn't going to get anywhere
Ok, so if you can't factor out 3 OR 19 then do I factor 40?
i'm so lost -.-
Factoring the quadratic will require use of the 3, the 19, and the 40
Stumped?
yes -.-
Actually, we have to find two numbers that add to get 19, but multiply to get -120 a + b = 19 ab = -120
I'll just explain how I figured it out that way you can understand the reasoning.
So first I just thought of two numbers that might work. First I tried 20 and -6 since 20 x -6 = -120. However, 20 - 6 = 14, so that doesn't work. Then I tried 30 and -4. 30 x -4 = -120, but 30 - 4 = 26. Now I know that the bigger number will be between 20 and 30. The only number that works is 24 and - 5 since 24 x -5 = -120 and 24 - 5 = 19
Now after doing this, I take the quadratic and "split the middle term" 19x so that 24x - 5x = 19x Then I replace the expression appropriately in the quadratic: 3x^2 + 19x - 40 = 0 3x^2 + 24x - 5x - 40 = 0 Now from here, I place the first two terms and last two terms within a set of parentheses: (3x^2 + 24x) + (-5x - 40) = 0 And afterwards, I factor the first two terms; then factor the last two terms to get: 3x(x + 8) - 5(x + 8) = 0 Now I see that x + 8 is also common to both terms so I factor that out as well to get: (x + 8)(3x - 5) = 0 From here, you can use the zero product property to finish finding the x-intercepts.
so then you use FOIL to finish?
Zero Product Property is not the same as FOIL. If you FOILed, you would only get the quadratic back. That's the opposite of what we want to do. We are trying to solve for x which would tell us what the x-intercepts are.
ok so then I would do x+8=0 and 3x-5=0? and solve them seperately?
Precisely
oooooh ok! so the answer is x=-8 and x=5/3
Bingo. So you found the x values. And now, you end by explicitly stating: The x-intercepts are -8 and 5/3. Any time you solve a word problem, you always end with a concluding statement.
Gotcha! thank you (:
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