Find x and y if: (5y+3xi)+(2x- 7yi)=11-27i How do I solve this?
the real terms are equal and the imaginary terms are equal 5y+2x=11 and 3x-7y=-27
Yup I got that far, I'm just stuck after that.
6x+15y=33 -6x+14y=54 29y=87 y=3 substitute back and get 5(3)+2x=11 2x=-4 x=-2 check (5(3)+3(-2)i)+(2(-2)- 7(3)i)=11-27i 15-6i+-4-21i=11-27i 11-27i=11-27i
Where does the 29y=87 come from? What was each term multiplied by?
add those two equations together
I see that, but wouldn't you have had to alter the original equations to get the both to equal 6 and -6?
Ohhhh! Nevrmind, I had the first equation written as 5x+2y=11:) Sorry
so multiple it by 2 and the other one by 3
no problem. glad you understand. let me know if anything else seems confusing
Thank you sooo much mate!!
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