How do I simplify
(2i^7)(3i-4)

Question

anonymous · Answer

Use distributive property?

anonymous · Answer

Elaborate please... do the imaginary numbers affect it?

anonymous · Answer

that 3i has an exponent of one when multiply number with an exponent you don't add them unless they have like bases.., 
2x3=6i^7+1
2i^7x4= 8i^7
6i^7-8i^7=
now that our exponents are the same you must subtract.(above) 
which gives you..,
-2i^7

anonymous · Answer

I appriciate your effort, but according to Wolfram Alpha that's incorrect: http://www.wolframalpha.com/input/?i=%282i^7%29%283i-4%29

anonymous · Answer

first, you have i^7, that's -i
So you'll have (-2i)(3i-4)
Then you'll have 6+8i (By using distributy)

whpalmer4 · Answer

$$(2i^7)(3i-4) = 6i^7*i - 8i^7 = 6i^8 - 8i^7$$
$$i^2=-1$$$$ i^4=-1*-1=1$$
$$6i^8-8i^7=6*1*1-8*1*(-1)*i=6-8i$$

anonymous · Answer

i=i
i^2=-1
i^3=-i
i^4=1
i^5=i
i^6=-1
i^7=-i
i^8=1 
And to infinity

whpalmer4 · Answer

Sorry, $$6+8i$$

anonymous · Answer

oh okay i see where i went wrong thanks.., i should have solved for i after distributing..,