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Mathematics 18 Online
OpenStudy (anonymous):

Hello, http://img856.imageshack.us/img856/9470/35e114b40f474ab79930144.png Is the exercise I am on, I have solved A, yet segment B is something which my textbook has not covered previously, could someone please explain this to me. Thank you so much!

OpenStudy (anonymous):

If you dont wish to open an external link I have uploaded it here:

OpenStudy (anonymous):

ok, that is one annoying question

OpenStudy (anonymous):

you matched each graph with the proper mean and Standard deviation?

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

what color is mean -1

OpenStudy (anonymous):

Histogram A: \[\mu = -1 , \sigma=3\] Histogram B: \[\mu = 2 , \sigma=0.5\] Histogram C: \[\mu = 1 , \sigma=1\]

OpenStudy (anonymous):

a proportion is just a fraction. top of fraction is frequency at the mean, bottom is the frequency of "standard deviation" moves to the right of the mean number

OpenStudy (anonymous):

So the answer to one histogram A's proportion would be \[\frac{ 30 }{ 3 } = 10\]

OpenStudy (anonymous):

30/17

OpenStudy (anonymous):

30 is at -1, 3 spots to the right is at 2

OpenStudy (anonymous):

which id say is about 17

OpenStudy (anonymous):

okay, 30/17 is about 1.76 in my answer book it reads that the answer should be 0.34 or 34% for histogram A

OpenStudy (anonymous):

and histogram B should be 39% and C 31.5%

OpenStudy (anonymous):

thanks for taking the time to help me by the way :)

OpenStudy (anonymous):

i got it

OpenStudy (anonymous):

it will be 200 divided by the added frequencies between the mean and 3 standard deviations to the right

OpenStudy (anonymous):

that gives me a solution of 35% though :(

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