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Factor completely: 16x2 + 40x + 25
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do you know how to slide and divide?
You've got a polynomial that has perfect squares for its x^2 and x^0 terms. What would happen if you multiplied (ax+b)(ax+b) where a = sqrt{16} and b = sqrt{25}?
multiply the last number by 16, then divide by 16
I don't know, but my teacher taught me slide and divide and it works best for me at least
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(4x+5)(4x+5)
We've got a polynomial of form ax^2+bx+c where a and c are squares. we know that (ax+b)(ax+b) = a^2x^2 + 2abx + b^2 so we just need to verify that 2ab = 40 (the coefficient of x^1 in our polynomial to be factored). 4*4=16, 5*5 = 26, and 2*4*5 = 40, so essentially by inspection we were able to factor it as (4x+5)^2.
Thanks
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