the length of a rectangle is 3in longer than the width and that the perimeter of the rectangle is 78. Set up an equation involving only W, the width of the rectangle
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OpenStudy (aravindg):
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OpenStudy (anonymous):
thank you
OpenStudy (ajprincess):
Let the width of the rectangle be w and length be l.
l=w+3
Perimeter=2(l+w)
78=2(w+3+w)
Try simplfyng this and u will get the required equation.
Can u do it @nburgher?
OpenStudy (anonymous):
the width would be 18 and length is 21
OpenStudy (ajprincess):
ya u r right:) bt u need to write only the equation
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OpenStudy (anonymous):
ok. Using the same length from above, find a new perimeter if the new width is 4 more than one-third of the length
OpenStudy (ajprincess):
length is 21. what is 1/3 of it?
OpenStudy (ajprincess):
(1/3)*21=?
OpenStudy (anonymous):
7
OpenStudy (ajprincess):
new width is 4 more than 7. so what will be it?
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OpenStudy (anonymous):
so the equation would be P=2(21)+2(7+4)?
OpenStudy (ajprincess):
ya:)
OpenStudy (anonymous):
thank you very much. I have been stuck on this for days