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\[integrate f(x,y)=\frac{ y }{ \sqrt{1+9x ^{4}} } \] over the curve C: y=x ^{3} from (2,8) to (0,0)
It has been a little while since cal 2, but this looks like a trig substitution problem. check with your book but let y=x^3, \[\sqrt{1+9x^2}\]=sec(theta), x=tan(theta), dx=sec^2(theta)d(theta).
This reduces to the integration of (tan^3(theta))(sec(theta))
Thank you :)
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