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Collect like terms. 31/9u+4/9v-17/9u+12/9v
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again lets group \[\frac{31}{9}u-\frac{17}{9}u=?\] looks bad, but it is not, because the denominators are the same
and \[\frac{4}{9}v+\frac{12}{9}v=?\]
\[\frac{31}{9}u-\frac{17}{9}u=\frac{31-17}{9}u=\frac{14}{9}u\] for the \(u\) part
\[\frac{4}{9}v+\frac{12}{9}v=\frac{4+12}{9}v=\frac{16}{9}v\] for the \(v\)
not too bad, right?
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so it would be \[\frac{ 14 }{ 9 }u+\frac{ 16 }{ 9 }v\]?
ya
yes
Thank you, it really helped :)
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