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The members of an organization are 10 men and 11 women. What is the probability that a committee of three selected at random is all female?
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Sorry wrong subject!
If there are 10 men and 11 women, assuming that there are no wierd mixed gender people, there are 21 people in total. The possibility of choosing one woman out of 21 is 11 / 21. The possibility of the next choice being a woman is 10 / 20. (one woman was already chosen) The possibility of the last choice being a woman is 9 / 19. This means that 11 x 10 x 9 / 21 x 20 x 19 (just multiply the fractions together) and you get 99/798.
Got answer from Yahoo answer :) they had better explanation than I did.
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