Question

Please help!

Answer 1

What do you need help with?

Answer 2

how I dont understand all this be solve and what match with what

Answer 3

I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?

Answer 4

Yes, cuz i have no idea.

Answer 5

Okay, well. Do you want me to explain it well? Or are you just looking for a solution?

Answer 6

Yes, please i dont understand each of this

Answer 7

Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\]
We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]

Answer 8

So does it match with 3 or 2?

Answer 9

So, I believe you're right when you put B, because it is the "greatest" solution.

Answer 10

ok

Answer 11

Let's move on to the next one.

Answer 12

sure

Answer 13

\[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]

Answer 14

So this match with 3

Answer 15

Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.

Answer 16

ok take your time

Answer 17

\[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]

Answer 18

I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.

Answer 19

Oh, wait! I forgot to flip the sign one moment.

Answer 20

\[z<-3/5\] you flip the sign because you divided by a negative.

Answer 21

got a decimall number

Answer 22

\[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]

Answer 23

Yeah, let me relook over my math for the 3rd one.

Answer 24

@zepdrix all this still confusing to me

Answer 25

Can you help me?

Answer 26

Which one you stuck on? D:

Answer 27

all of them

Answer 28

I will be right back in a few minute

Answer 29

K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\]

This is a spot where you have to be careful.
Multiplying or Dividing by a negative value will FLIP the inequality sign.

So we'll proceed by dividing by -7,\[\large z \lt -2\]

Answer 30

Take a look at those steps, see if they make sense to you.

So let's think about this inequality a second.

Z is LESS THAN -2.
The LARGEST integer that would make this inequality true would be -3 correct?
Because -3 is less than -2.

Answer 31

No sorry for late answer :( still didnt make sense

Answer 32

Which part? :o

Answer 33

Does first match up with 2, is that what you meant?

Answer 34

I didn't do the first one, I was working on the last one.

Answer 35

I was trying to find out where i m wrong

Answer 36

try an to understand how all of them match correctly

Answer 37

Well look at them one at a time.

In each case, you're given an inequality with ONE VARIABLE.
Since the inequality has only one variable, we can solve for that variable.

It looks like you have the wrong answer for the 4th equation.
Scroll back up, I listed detailed steps on how to solve the 4th one.
See if any of the steps confuse you.

Answer 38

Can you tell me others also, cuz i m having confusion 3rd one

Answer 39

I m ridiculously crazy from many hours to understand all of it

Answer 40

\[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\]

Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign.

Dividing both sides by -5 gives us,\[\large z \lt 1\]
See how the inequality sign flipped?

Answer 41

What is the LARGEST integer below the number 1?

That is the value that will make z true in the 3rd equation.

Answer 42

sorry

Answer 43

1 is not less than 1 :D 1 is equal to 1. Think one lower than that.

Answer 44

0

Answer 45

how do you got zero

Answer 46

Am i wrong?

Answer 47

@satellite73 can you explain me all this

Answer 48

i cant still understand all of them

Answer 49

@Carl_Pham can you help me wit it

Answer 50

@AravindG help

Answer 51

YOU just need to open the brackets and bring all constants to RHS

Answer 52

Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it

Answer 53

@satellite73 can you help me ?

Answer 54

@mathstudent55 can you able to help me with this?

Answer 55

@Faman39 well i think most of them have been solved above .tell me where exactly u have doubt

Answer 56

ok

Answer 57

actually i m confuse because, i think whenever i tried to solve n match, i cant

Answer 58

I dont know, why my head isnt working today, where everyone did so great

Answer 59

Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.

Answer 60

Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys