Please help ASAP!! What is the solution set of |x – 2| > 3?
x + 2 > 3 x > 1 All numbers greater than 1 would be in the solution set.
faulty...... 2 is greater than 1 but 2 is most emphatically not in the solution set
@zugzwang, that's what I was going to say! It doesn't work..
The error was when it was (inaccurately) assumed that |x - 2| = x + 2 So back to the inequality |x - 2| > 3 Well, what if we just remove the absolute value? x - 2 > 3
Would I have to solve for x - 2 > 3 and also x - 2 < 3?
It may be easier to see it without the the translation first.... What do you get if I give you |y| > 3 ?
y > 3, and also y < -3 right?
Correct. Now just replace y with x - 2, and you have what you need :)
So x > 5, and x < -1? :)
You got it :)
You can try it too, check those that are smaller than -1 and also check those larger than 5 You'll see it works every time
Thanks!
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