Suppose an investment of $2,300 doubles in value every decade. The function gives the value of the investment after x decades. f(x)=2300*2^x How much is the investment worth after 2 decades?
(1 point)$2,355,200
$92,000
$46,000
$9,200

Question

Suppose an investment of $2,300 doubles in value every decade. The function  gives the value of the investment after x decades. f(x)=2300*2^x How much is the investment worth after 2 decades?
 (1 point)$2,355,200
$92,000
$46,000
$9,200

anonymous · Answer

Can one of you help me?(:

saifoo.khan · Answer

Replace x with 2.

whpalmer4 · Answer

f(x) = 2300*2^x
x = number of decades = 2

f(2) = 2300*2^2 = 2300*4 = ?

anonymous · Answer

I ried that, but I didnt know if it was right or not. Bc I got the first one

anonymous · Answer

Why would I multiply by 4 at the end?

whpalmer4 · Answer

2^2 = (2)(2) = 4

so $2300*4 =

anonymous · Answer

9,200?

whpalmer4 · Answer

Do you understand what 2^x means?

whpalmer4 · Answer

or $$2^x$$

anonymous · Answer

Yeah

whpalmer4 · Answer

Okay, that's why you multiply $2300 by 4 :-)  What if the number of decades was 5, what would the answer be?

anonymous · Answer

Ughhh, i am so confused. I thought I was supposed to do it like this.

2300*2^2 
and then get 9200! Right?

whpalmer4 · Answer

No, I was asking for the case where the number of decades is 5.  x=5

whpalmer4 · Answer

So the formula would be f(5) = 2300*2^5 = ?

anonymous · Answer

I know, but I am talking about this problem. Was I right abpout what I just said?

whpalmer4 · Answer

Yes, for this problem the answer is 9200.  I was attempting to make sure that you understood what we actually did, that's why I asked you for the answer if the number of decades is 5.

anonymous · Answer

did you get it right @Heyy_Girl_Heyy      ???