Question

i really need help please!
number 1 and two i'll attach it please help!

Answer 1

@SWAG

Answer 2

Okay, can you plot those points on the first grid, and connect them with straight lines?

Answer 3

ok look i got the answer key n my teacher thinks am cheating can u help me make it look like i did it on my own? because i need to write everything on a piece of paper and proof to her i did it on my own HERES THE ANSWER KEY

Answer 4

i need to get an answer like both of these and she noice tht my answer look like them?

Answer 5

What I'm telling you will allow you to do the problem on your own even without the answer key...

Answer 6

Which is sort of the point of whole thing!

Answer 7

this is how i answered number one
All the sides are congruent and the consecutive sides are perpendicular so its a square. s= 3sqrt2 P= 4s = 4 (4.24)= 17 A= s^2=(4.24)^2= 18 square units units
this is how i answered number 2
All the sides are congruent and consecutive sides are not perpendicular so its a rhombus. P=4s=4(5.39)=4sqrt29 The diagonal for (-3,-3) and (4,4) length is 7sqrt

can u please help me ?

Answer 8

I'm very good at explaining, it will be painless :-)

Answer 9

like make me figure it out step by step like solving?

Answer 10

just please help i will get expelled if i don proof this! im scared

Answer 11

Okay, well, first question: can you plot those 4 points and draw the straight lines connecting them? That's the first step.

Answer 12

the answer key has it?

Answer 13

how do you solve for it to get hose points?

Answer 14

Yes, okay, I guess I'll take it for granted that you could plot those points and recognize a square when you see one.

Now you have to find the perimeter and area of the square. Do you know the formula for the perimeter of a square and the area of a square?

Answer 15

no i dont :(

Answer 16

no

Answer 17

Okay, the area of a rectangle is just the length * width, and squares of course are just special cases of rectangles where the length and width are the same. The perimeter of any figure is just the distance around it. With a square, that is going to be 4 * side of the square, with a rectangle it would be 2 * length + 2 * width.

Answer 18

like howw to do we ge this? ==> s = 4.24

Answer 19

We'd be all set, except we don't know what the length of the sides of our square is!

Answer 20

Do you know the Pythagorean theorem, which relates the sides of a right triangle with the hypotenuse?

Answer 21

oh lets find i then and no could you help me with tha?

Answer 22

Pythagorean theorem says if we know any 2 sides in a right triangle, we can find the third one with this equation:

\[A^2 + B^2 = C^2\]
(if they are labeled as in my drawing)

Answer 23

Now take a look at that graph we made. Isn't there a right triangle made by the x-axis and the y-axis, and the line connecting (0,3) and (3,0)?

Answer 24

oh like how dop i figure out this? ==> The sides are all congruent and consecutive sides are perpendicular. This is a square I GUESS THIS IS WHY SHE THINKS I COPIED

Answer 25

@whpalmer4

Answer 26

Do you see the triangle I'm talking about?

Answer 27

yes

Answer 28

Okay, does it remind you at all of the triangle I drew in the Pythagorean theorem explanation?

Answer 29

The answer I'm looking for here is "yes" :-)

Answer 30

yeah

Answer 31

Okay, we know the length of two sides, the one from (0,0) to (3,0) and the one from (0,0) to (0,3), right? What are those lengths?

Answer 32

how do i find the lengths idk how?

Answer 33

Well, let's look at going from (0,0) to (3,0). Isn't that just moving 3 points down the number line?

Answer 34

yeah it looks like th triangle u drew

Answer 35

*that

Answer 36

So, from (0,0) to (3,0) is just a distance of 3, right? Because the y values are equal, we can just subtract the x values.

Answer 37

Similarly, from (0,0) to (0,3) is also a distance of 3. Here the x values are identical, so we can just subtract the y values.

Answer 38

so what do we do ?

Answer 39

Do you agree?

If so, what is the distance between (5,1) and (11,1)?

Answer 40

are we talking about number one? sorry i get confused really when is different numbers

Answer 41

@whpalmer4

Answer 42

I'm trying to help you understand this, so I'm asking you a few questions not found in the problem.

Answer 43

oh

Answer 44

So, what is the distance between the points (5,1) and (11,1)?

Answer 45

5?

Answer 46

Close. How many ticks over do you count when you count from 5 to 11?

Answer 47

5 to 6, 6 to 7, 7 to 8, 8 to 9, 9 to 10, 10 to 11. That's 6.

Answer 48

It is not a coincidence that 11-5 = 6...

Okay, so the distance between two points, if they both have the same x value, is just the difference in their y values. If they both have the same y value, the distance is the difference in their x values. Clear as mud?

Answer 49

From (0,0) to (3,0), they have identical y values (y = 0), so we take the difference of their x values (3 - 0 = 3) and it is therefore a distance of 3 from (0,0) to (3,0).

From (0,0) to (0,3), they have identical x values (x = 0), so we take the difference of their y values (3 - 0 = 3) and it is therefore a distance of 3 from (0,0) to (0,3).

That means we have two sides of our triangle in the middle of the square figured out, and they are both 3. A = B = 3. Now, we can use the Pythagorean theorem to find out what C is, and we'll know the side of our square!

\[A^2 + B^2 = C^2\]\[3^2+3^2 = C^2\]\[9+9=C^2\]\[18 = C^2\]
Do you know about square roots?

Answer 50

The square root of a number is another number which if multiplied by itself gives you the first number. For example, the square root of 100 is 10, because 10*10 = 100. Is there a number which multiplied by itself gives you 18?

Answer 51

1*1 = 1
2*2 = 4
3*3 = 9
4*4 = 16
5*5 = 25

So, the number must be somewhere between 4 and 5. Because 18 is closer to 16 than it is to 25, the number must be closer to 4 than to 5.

Are you still there? @blonfdashjessica22

Answer 52

If you type 18 into your calculator and press the square root key, you'll find that the square root is the number given for the side length in the answer key.

In general, to find the distance between two points, you use the Pythagorean theorem. If you have a point (x1,y1) and a point (x2,y2), the distance between them will be

\[\sqrt{(x_1-x_2)^2 + (y_1-y_2)^2}\]

If the x values are identical, it simplifies to y1-y2. If the y values are identical it simplifies to x1-x2.

I already told you the formulas to find the area and perimeter. You know it is a square because all 4 sides have the same length and the angles are identical.

Okay, for the second problem, you are going to have to use the distance formula to find the lengths of the sides and the diagonals. The area of a rhombus is 1/2 * the first diagonal * the second diagonal.

Good luck, you're going to need it!